find_last_index()

Gets the index at which the last occurrence of value is found.

Implementation

Args: array: List to search. filter_by: Value to search for. Returns: Index of the matched value, otherwise -1.

Example

find_last_index([1, 2, 3, 4, 5], 3)

Expected output: 2

Alternative usage:

find_last_index([1, 2, 3, 4, 5], 6)

Expected output: -1

Source Code

                        def find_last_index(
    array: List[T], filter_by: Union[Callable[[T], bool], Dict[str, Any], Any]
) -> int:
    if callable(filter_by):
        predicate = filter_by  # type: ignore
    elif isinstance(filter_by, dict):

        def predicate(x):  # type: ignore
            return all(x.get(k) == v for k, v in filter_by.items())  # type: ignore
    else:

        def predicate(x):
            return x == filter_by  # type: ignore

    for idx in builtins.range(len(array) - 1, -1, -1):
        try:
            if predicate(array[idx]):
                return idx
        except Exception:
            continue
    return -1
                    